CBSE
2026
Class Class 10 · Mathematics
1 Marks · Mcq
✅ Verified
Given that $\sin 2\alpha = \dfrac{\sqrt{3}}{2}$, the value of $\sin 3\alpha$ is :
A. $\dfrac{3\sqrt{3}}{4}$
B. $\dfrac{1}{2}$
C. $1$
D. $\dfrac{\sqrt{3}}{4}$
✅ Answer & Solution
✅ Correct Answer: C
Step 1: $$\sin 2\alpha = \frac{\sqrt{3}}{2} = \sin 60^\circ$$
Step 2: $$2\alpha = 60^\circ \Rightarrow \alpha = 30^\circ$$
Step 3: $$\sin 3\alpha = \sin(3 \times 30^\circ) = \sin 90^\circ = 1$$
Correct option : (C)
✅ Verified by Super Admin