CBSE
2026
Class Class 10 · Mathematics
1 Marks · Mcq
✅ Verified
When $\sin A=\dfrac{1}{3}$, the value of $\cot A$ is
A. $\dfrac{2\sqrt{2}}{3}$
B. $2\sqrt{2}$
C. $\dfrac{1}{2\sqrt{2}}$
D. $3$
✅ Answer & Solution
✅ Correct Answer: B
Step 1: $\sin A=\dfrac{1}{3}=\dfrac{\text{perpendicular}}{\text{hypotenuse}}$, so $p=1,\ h=3$.
Step 2: By Pythagoras theorem, base $$b=\sqrt{h^2-p^2}=\sqrt{9-1}=\sqrt{8}=2\sqrt2$$
Step 3: $$\cot A=\frac{\text{base}}{\text{perpendicular}}=\frac{2\sqrt2}{1}=2\sqrt2$$
Answer: (B) $2\sqrt{2}$
✅ Verified by Super Admin
