CBSE
2026
Class Class 10 · Mathematics
1 Marks · Mcq
✅ Verified
The value of $\left(\dfrac{1}{3}\cot^2 30^\circ - \dfrac{1}{2}\sec^2 60^\circ\right)$ is :
A. $-1$
B. $-2$
C. $\dfrac{5}{8}$
D. $\dfrac{7}{8}$
✅ Answer & Solution
✅ Correct Answer: A
Step 1: $\cot 30^\circ = \sqrt{3}$ and $\sec 60^\circ = 2$.
Step 2: $$\frac{1}{3}\cot^2 30^\circ = \frac{1}{3}(\sqrt{3})^2 = \frac{3}{3} = 1$$
Step 3: $$\frac{1}{2}\sec^2 60^\circ = \frac{1}{2}(2)^2 = 2$$
Step 4: $$1 - 2 = -1$$
Correct option : (A)
✅ Verified by Super Admin