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Class 12 › Physics › Electric Potential & Capacitance
CBSE2022Class Class 12 · Physics3 Marks · Short✅ Verified
A short electric dipole has dipole moment 16×10⁻⁹ C·m. Find the electric potential at a point 0.6 m from centre, on a line making 60° with the dipole axis.
✅ Answer & Solution
Given:
• Dipole moment, p = 16 × 10⁻⁹ C·m
• Distance, r = 0.6 m
• Angle, θ = 60°
Formula:
V = kp cosθ / r²
Calculation:
V = (9 × 10⁹ × 16 × 10⁻⁹ × cos 60°) / (0.6)²
V = (9 × 10⁹ × 16 × 10⁻⁹ × 0.5) / 0.36
V = (9 × 16 × 0.5) / 0.36
V = 72 / 0.36
V = <b>200 V</b>
∴ <b>Electric potential at the given point = 200 V</b>
