CBSE
2021
Class Class 12 · Physics
1 Marks · Mcq
✅ Verified
When two charged capacitors having capacitance and potential C₁, V₁ and C₂, V₂ respectively, are joined with a wire, the common potential will be
A. (C₁V₁ + C₂V₂)/(C₁+C₂)
B. (C₁V₁ − C₂V₂)/(C₁+C₂)
C. C₁V₁/C₂V₂
D. (V₁+V₂)/2
✅ Answer & Solution
✅ Correct Answer: A
✅ Correct Answer: (A) (C₁V₁ + C₂V₂) / (C₁ + C₂)
📌 Concept: Conservation of Charge
Step 1 — Total Charge:
Q_total = Q₁ + Q₂ = C₁V₁ + C₂V₂
Step 2 — Total Capacitance:
C_total = C₁ + C₂
Step 3 — Common Potential:
V_common = Q_total / C_total
V = (C₁V₁ + C₂V₂) / (C₁ + C₂)
✅ Verified by Super Admin
