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Class 12 › Physics › Electric Potential & Capacitance
CBSE2021Class Class 12 · Physics3 Marks · Short✅ Verified
(A) Calculate the potential at point P due to charge 4×10⁻⁷ C located 9 cm away. (B) Obtain the work done in bringing charge 2×10⁻⁹ C from infinity to point P. Does the answer depend on the path?
✅ Answer & Solution
📌 Part (A) — Potential at Point P:
Given:
• Charge, Q = 4 × 10⁻⁷ C
• Distance, r = 9 cm = 0.09 m
Formula: V = kQ / r
Calculation:
V = (9 × 10⁹ × 4 × 10⁻⁷) / 0.09
V = 3600 / 0.09
V = <b>4 × 10⁴ V</b>
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📌 Part (B) — Work Done:
Given:
• Charge, q = 2 × 10⁻⁹ C
• V at P = 4 × 10⁴ V
Formula: W = qV
Calculation:
W = 2 × 10⁻⁹ × 4 × 10⁴
W = <b>8 × 10⁻⁵ J</b>
Path Dependence:
→ Work done does <b>NOT depend on the path</b>.
→ Reason: <b>Electric force is conservative</b> — work depends only on initial and final positions.