CBSE
2019
Class Class 12 · Physics
2 Marks · Short
✅ Verified
A 10 µF capacitor is charged by a battery of e.m.f. 100 V. The electrostatic energy stored in the capacitor is
✅ Answer & Solution
✅ Correct Answer: (A) 0.05 J
Given:
• Capacitance, C = 10 µF = 10 × 10⁻⁶ F
• Voltage, V = 100 V
Formula:
U = ½ × C × V²
Calculation:
U = ½ × (10 × 10⁻⁶) × (100)²
U = ½ × 10⁻⁵ × 10⁴
U = ½ × 0.1
U = <b>0.05 J</b>
✅ Verified by Super Admin
