One charge particle is moved from A→C→B and another from A→D→B in a...

Question

One charge particle is moved from A→C→B and another from A→D→B in a uniform external electric field. For which charge particle more work is needed?

Accepted Answer

📌 Answer: Work done is the same for both paths. Key Concept: Electrostatic force is conservative in nature. Explanation: • In a conservative field, work done depends only on the initial and final points. • It does NOT depend on the path taken. • Both particles start at A and end at B. W = q × (V_A − V_B) Since V_A and V_B are fixed (same for both particles): W₁ (A→C→B) = W₂ (A→D→B) ∴ Equal work is done for both paths.

🔔 Email Updates Lein