CBSE
2020
Class Class 12 · Physics
2 Marks · Short
✅ Verified
A capacitor of capacitance 50 µF is charged to a potential of 1000 V. Calculate the energy stored in the capacitor.
✅ Answer & Solution
Given:
• Capacitance, C = 50 µF = 50 × 10⁻⁶ F
• Potential, V = 1000 V
Formula:
U = ½ × C × V²
Calculation:
U = ½ × (50 × 10⁻⁶) × (1000)²
U = ½ × 50 × 10⁻⁶ × 10⁶
U = ½ × 50
U = <b>25 J</b>
∴ Energy stored in the capacitor = <b>25 Joules</b>
✅ Verified by Super Admin
