In ΔABC, P and Q are points on sides AB and AC respectively such th...

Question

In ΔABC, P and Q are points on sides AB and AC respectively such that PQ || BC. If AP : PB = 3 : 2, then PQ : BC is equal to:

Accepted Answer

Since PQ || BC, $	riangle APQ \sim 	riangle ABC$. $AB = AP+PB = 3k+2k = 5k$. $$\frac{PQ}{BC}=\frac{AP}{AB}=\frac{3k}{5k}=\frac{3}{5}$$