CBSE
2026
Class Class 10 · Mathematics
2 Marks · Short
✅ Verified
(A) In $\triangle ABC$, $DE \parallel BC$. If $AD = x$, $DB = x-2$, $AE = x+2$ and $EC = x-1$, then find the value of $x$.
✅ Answer & Solution
By Basic Proportionality Theorem (Thales' theorem), since $DE \parallel BC$: $\frac{AD}{DB} = \frac{AE}{EC}$. $\frac{x}{x-2} = \frac{x+2}{x-1}$. $x(x-1) = (x+2)(x-2)$. $x^2-x = x^2-4$. $-x = -4$. $x = 4$.
✅ Verified by Super Admin
