The value of $\cos 0^\circ$ will be:

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Answer: $$\cos 0^\circ = 1$$ The standard value table: $	heta$ $0^\circ$ $30^\circ$ $45^\circ$ $60^\circ$ $90^\circ$ $\sin	heta$ 0 $\frac{1}{2}$ $\frac{1}{\sqrt{2}}$ $\frac{\sqrt{3}}{2}$ 1 $\cos	heta$ 1 $\frac{\sqrt{3}}{2}$ $\frac{1}{\sqrt{2}}$ $\frac{1}{2}$ 0 Worth noting: $$\sin 0^\circ = 0 \quad 	ext{but} \quad \cos 0^\circ = 1$$ $$\sin 90^\circ = 1 \quad 	ext{but} \quad \cos 90^\circ = 0$$ The sine and cosine rows are exact reverses of each other. Important: Both $\sin	heta$ and $\cos	heta$ always lie between $-1$ and $1$, so options (c) 2 and (d) $-1$ could never arise for an angle in $[0^\circ, 90^\circ]$. Correct option: (a) 1

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$\theta$	$0^\circ$	$30^\circ$	$45^\circ$	$60^\circ$	$90^\circ$
$\sin\theta$	0	$\frac{1}{2}$	$\frac{1}{\sqrt{2}}$	$\frac{\sqrt{3}}{2}$	1
$\cos\theta$	1	$\frac{\sqrt{3}}{2}$	$\frac{1}{\sqrt{2}}$	$\frac{1}{2}$	0

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