Ten capacitors, each of capacitance $1\,\mu F$, are connected in pa...

Question

Ten capacitors, each of capacitance $1\,\mu F$, are connected in parallel to a source of 100 V. The total energy stored in the system is equal to:

Accepted Answer

Step 1: For capacitors in parallel, $C_{total} = nC = 10 	imes 1\,\mu F = 10\,\mu F$. Step 2: Energy stored: $U = \dfrac{1}{2}CV^2$. Step 3: Substitute: $U = \dfrac{1}{2}	imes 10	imes10^{-6}	imes(100)^2$. Step 4: $U = \dfrac{1}{2}	imes 10	imes10^{-6}	imes 10^4 = 10^{-2}$ J. Answer: $10^{-2}$ J (Option A).

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