Initial resistance: $R_0 = V/I - r = 100/10 - 1 = 9\ \Omega$

Resistance at 320°C ($\Delta T = 300$°C):

$$R = R_0(1 + \alpha \Delta T) = 9(1 + 3.70 \times 10^{-4} \times 300) = 9 \times 1.111 = 10\ \Omega$$

Steady current:

$$I = \frac{E}{R + r} = \frac{100}{10 + 1} = \frac{100}{11} \approx 9.09 \text{ A}$$

Power consumed by battery (internal resistance $r$):

$$P = I^2 r = \left(\frac{100}{11}\right)^2 \times 1 \approx 82.6 \text{ W}$$