A conducting wire connects two charged conducting spheres of radii ...

Question

A conducting wire connects two charged conducting spheres of radii r₁ and r₂ such that they attain equilibrium with respect to each other. The distance of separation between the two spheres is very large as compared to either of their radii. Find the ratio of the magnitudes of the electric fields at the surfaces of the spheres of radii r₁ and r₂.

Accepted Answer

Concept: When two conductors are connected by a wire, they reach the same potential.

Step 1: Equate potentials
V₁ = V₂
kq₁/r₁ = kq₂/r₂

Therefore: q₁/q₂ = r₁/r₂

Step 2: Electric field at surface
E = kq/r²

Step 3: Take ratio
E₁/E₂ = (q₁/q₂) × (r₂/r₁)²
E₁/E₂ = (r₁/r₂) × (r₂/r₁)²
E₁/E₂ = r₂/r₁

Answer: E₁ : E₂ = r₂ : r₁

Conclusion: Smaller sphere has stronger surface field.

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