CBSE
2026
Class Class 10 · Mathematics
1 Marks · Mcq
✅ Verified
The $n^{th}$ term of the A.P. $\dfrac{-1}{3},\ \dfrac{2}{3},\ \dfrac{5}{3},\ \dfrac{8}{3},\ \ldots$ is :
A. $3n - 4$
B. $n - \dfrac{4}{3}$
C. $\dfrac{n-2}{3}$
D. $\dfrac{n-4}{3}$
✅ Answer & Solution
✅ Correct Answer: B
Step 1: First term $a = \dfrac{-1}{3}$.
Step 2: Common difference $$d = \frac{2}{3} - \left(\frac{-1}{3}\right) = \frac{3}{3} = 1$$
Step 3: $$a_n = a + (n-1)d = \frac{-1}{3} + (n-1)(1) = n - 1 - \frac{1}{3} = n - \frac{4}{3}$$
Correct option : (B)
✅ Verified by Super Admin
