CBSE
2026
Class Class 10 · Mathematics
3 Marks · Short
✅ Verified
Two different dice are thrown together. Find the probability that the numbers obtained have :
(i) even sum,
(ii) even product.
✅ Answer & Solution
**Step 1 — Total number of outcomes.**
$$n(S) = 6 \times 6 = 36$$
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**(i) Even sum**
**Step 2 — When is a sum even?**
Sum is even when **both numbers are even** or **both numbers are odd**.
**Step 3 — Count.**
- Both even : $3 \times 3 = 9$ ways (from $\{2,4,6\}$)
- Both odd : $3 \times 3 = 9$ ways (from $\{1,3,5\}$)
$$n(E_1) = 9 + 9 = 18$$
**Step 4 — Probability.**
$$P(\text{even sum}) = \frac{18}{36} = \frac12$$
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**(ii) Even product**
**Step 5 — When is a product odd?**
The product is odd **only** when both numbers are odd.
$$n(\text{odd product}) = 3 \times 3 = 9$$
**Step 6 — Count the even products.**
$$n(E_2) = 36 - 9 = 27$$
**Step 7 — Probability.**
$$P(\text{even product}) = \frac{27}{36} = \frac34$$
$$\boxed{\text{(i) } \frac12 \qquad \text{(ii) } \frac34}$$
✅ Verified by Super Admin