A charge q = 1 mC is placed at point (1 m, 2 m, 4 m). Find the electric field at point P(0 m, -4 m, 3 m).
✅ Answer & Solution
<b>Given:</b><br>• q = 1 mC = 10⁻³ C<br>• Source position A(1, 2, 4)<br>• Field point P(0, -4, 3)<br><br><b>Step 1: Find position vector from charge to P</b><br>r = P - A = (0-1, -4-2, 3-4)<br><b>r = (-1, -6, -1)</b><br><br><b>Step 2: Find magnitude of r</b><br>|r| = √[(-1)² + (-6)² + (-1)²]<br>|r| = √(1 + 36 + 1)<br><b>|r| = √38 m</b><br><br><b>Step 3: Apply electric field formula</b><br>E = kq · r / |r|³<br><br><b>Step 4: Substitute values</b><br>E = (9 × 10⁹) × (10⁻³) × (-1, -6, -1) / (√38)³<br>E = (9 × 10⁶) × (-1, -6, -1) / (38√38)<br>E = (9 × 10⁶) / (38 × 6.16) × (-1, -6, -1)<br>E ≈ 3.84 × 10⁴ × (-1, -6, -1) N/C<br><br><b>Final Answer:</b><br><b>E ≈ -3.84 × 10⁴ î - 23.04 × 10⁴ ĵ - 3.84 × 10⁴ k̂ N/C</b>
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