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Class 12 › Physics › Electric Charge and Field
CBSE2024Class Class 12 · Physics2 Marks · Short✅ Verified
What is the electric flux through a cube of side 1 cm which encloses an electric dipole?
✅ Answer & Solution
<b>Answer: Net electric flux = 0</b><br><br><b>Reasoning using Gauss's Law:</b><br><br><b>Gauss's Law:</b><br>φ = q<sub>enclosed</sub>/ε<sub>0</sub><br><br><b>Step 1: Identify enclosed charges</b><br>An electric dipole consists of two charges: <b>+q and -q</b>.<br><br><b>Step 2: Calculate net enclosed charge</b><br>q<sub>enclosed</sub> = (+q) + (-q) = <b>0</b><br><br><b>Step 3: Apply Gauss's law</b><br>φ = 0/ε<sub>0</sub> = <b>0</b><br><br><b>Important Notes:</b><br>• Flux is <b>independent of the shape and size</b> of the closed surface<br>• Flux depends only on the <b>net charge enclosed</b><br>• Since net charge of dipole is zero, flux through any closed surface enclosing it is zero
