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Class 12 › Physics › Moving Charges and Magnetism
CBSE2023Class Class 12 · Physics5 Marks · Short✅ Verified
Derive the expression for the magnetic field due to a long solenoid.
✅ Answer & Solution
Consider a long solenoid with $n$ turns per unit length carrying current $I$.
Apply Ampere's circuital law to a rectangular Amperian loop ABCD:
- AB is inside the solenoid (parallel to axis), length $L$.
- CD is outside (field $\approx 0$).
- BC and DA are perpendicular (no contribution).
$$\oint \vec{B} \cdot d\vec{l} = B \cdot L + 0 + 0 + 0 = BL$$
Current enclosed = number of turns in length $L$ × $I$ = $nLI$