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Class 12 › Physics › Moving Charges and Magnetism
CBSE2014Class Class 12 · Physics1 Marks · Mcq✅ Verified
A current-carrying coil is placed in a uniform magnetic field of induction $B$. The current in the coil is $i$, it has $n$ turns, $A$ is the face area and the normal to the surface makes an angle $\theta$ with $B$. The torque on the coil is
A. $niAB\theta$
B. $niAB\cos\theta$
C. $niAB\sin\theta$
D. $niAB\tan\theta$
✅ Answer & Solution
✅ Correct Answer: C
Torque on a current-carrying coil in a magnetic field:
$$\tau = nIAB\sin\theta$$
where $\theta$ is the angle between the magnetic moment vector $\vec{m} = nIA\hat{n}$ and $\vec{B}$.
Hence the torque is $niAB\sin\theta$.
