CBSE
2026
Class Class 10 · Mathematics
1 Marks · Mcq
✅ Verified
If $\triangle ABC$ and $\triangle DEF$ are similar such that $2AB = DE$ and $BC = 8$ cm, then $EF$ is equal to:
A. 4 cm
B. 8 cm
C. 12 cm
D. 16 cm
✅ Answer & Solution
✅ Correct Answer: D
Since $\triangle ABC \sim \triangle DEF$, corresponding sides are proportional: $\frac{AB}{DE} = \frac{BC}{EF}$. Given $2AB = DE$, so $\frac{AB}{DE} = \frac{1}{2}$. Thus $\frac{BC}{EF} = \frac{1}{2} \Rightarrow EF = 2 \times BC = 2 \times 8 = 16$ cm.
✅ Verified by Super Admin