Chapter 9: Coconut Farm Ncert Solution Class 5th Mathematics (Math Mela)

NCERT Solution

Chapter 9: Coconut Farm Ncert Solution Class 5th Mathematics (Math Mela)

Class 5 · Mathematics (Math Mela) · Chapter 9: Coconut Farm · All Board · ENGLISH · 1 views

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✅ SOLUTIONS

Class 5

Chapter 9: Coconut Farm

Math Mela · NCERT Solutions

Class 5Math Mela (NCERT)Chapter 9

📚 Jump to a Section

Coconut Array & Let Us Play
Let Us Do — Multiplication/Division Facts
Patterns in Division & Place Value
Let Us Do — Word Problems & Puzzle
Mental Strategies — Try It & Let Us Solve
Susie's Farm & Let Us Learn to Divide
Let Us Solve — Word Problems
Kalpavruksha Coconut Oil
Division Using Place Value
Let Us Divide (a-d)
Let Us Do — Missing Numbers & Riddle
Let Us Solve — Final Word Problems
Vegetable Market & Final Divisions
Mathematical Statements

🥥 Coconut Array & Let Us Play

35÷1 = ? Multiplication fact for the second array (3 rows × 8 columns).

Solution

35 ÷ 1 = 35 (any number divided by 1 stays the same)

Second array: 3 rows × 8 columns = 24 coconuts

3 × 8 = 24 → 24 ÷ 3 = 8 and 24 ÷ 8 = 3

Let Us Play — Fill the circles so squares are products/quotients.

Sample Solution(many correct answers possible)

Square	Circle × Circle
72	36 × 2 (given)
60	10 × 6
48	8 × 6
36	9 × 4
24	4 × 6
40	5 × 8

Square	Circle ÷ Circle
54	108 ÷ 2
42	84 ÷ 2
56	112 ÷ 2

💡 For the last three (54÷?, 42÷?, 56÷?), any factor of that number works as the second circle — e.g., 54÷6=9, 42÷6=7, 56÷7=8.

✍️ Let Us Do — Multiplication/Division Facts

Q1. Solve and write two division facts each.

Solution

Multiplication	Division Facts
30×30=900	900÷30=30
15×60=900	900÷15=60 and 900÷60=15
400×8=3,200	3,200÷400=8 and 3,200÷8=400
200×16=3,200	3,200÷200=16 and 3,200÷16=200

🔍 Patterns in Division & Place Value

Q2. Division patterns — solve and notice patterns.

Solution

Problem	Answer	Problem	Answer
150÷3	50	500÷5	100
80÷4	20	500÷50	10
100÷10	10	300÷100	3
200÷20	10	440÷44	10
630÷63	10

Patterns in Division and Place Value — full tables.

Solution

Problem	Answer	Problem	Answer
1000÷10	100	1000÷100	10
2000÷2	1,000	2000÷20	100
3300÷3	1,100	3300÷300	11
1600÷4	400	3700÷37	100
4000÷40	100

Place value charts:

Problem	H	T	O
40÷10	—	—	4
400÷10	—	4	0
4000÷10	4	0	0
700÷70	—	1	0
1400÷100	—	1	4
220÷20	—	1	1
2200÷20	1	1	0

🌟 Pattern: dividing by 10 shifts every digit ONE place to the right (like reversing ×10)!

Problem	Answer
110÷11	10
860÷86	10
7500÷750	10
8800÷88	100
2400÷24	100
440÷22	20

✍️ Let Us Do — Word Problems & Puzzle

Q1-3. Sabina's cycling, Seema's notes, Diwali gift.

Solution

1. Sabina: 160÷20 = 8 km/day

2. Seema: 4200÷100 = 42 notes

3. ₹5500÷5 = ₹1,100 each. If ÷10 employees = ₹550 each — LESS per employee (more people sharing same total). To keep ₹1,100 each for 10 people: 10×1,100 = ₹11,000 needed

Q4. Place 1-8 so ÷, −, ×, + all work in the hexagon grid.

Solution

Layout: TopLeft ÷ TopMid = TopRight; TopLeft − MidLeft = BotLeft; TopRight × MidRight = BotRight; BotLeft + BotMid = BotRight

Top row: 6 ÷ 3 = 2
Middle: 5 4
Bottom row: 1 + 7 = 8

Check	Result
6 ÷ 3 = 2	✓
6 − 5 = 1	✓ (connects to bottom-left)
2 × 4 = 8	✓ (connects to bottom-right)
1 + 7 = 8	✓

All 8 digits (1-8) used exactly once! ✅ This puzzle likely has other valid solutions too — try swapping numbers systematically to find more.

Q5. Fill in the blanks (a-h).

Solution

Problem	Answer
(a) ___ ÷ 18 = 100	1,800
(b) ___ ÷ 10 = 610	6,100
(c) ___ ÷ 100 = 72	7,200
(d) ___ ÷ 100 = 10	1,000
(e) 870 ÷ ___ = 87	10
(f) ___ ÷ 100 = 70	7,000
(g) 200 ÷ ___ = 2	100
(h) 130 ÷ ___ = 13	10

🧠 Mental Strategies — Try It & Let Us Solve

Try It! 1-6 (split/halve strategies).

Solution

Problem	Method	Answer
1) 64÷4	32÷4 + 32÷4 = 8+8	16
2) 265÷5	250÷5 + 15÷5 = 50+3	53
3) 1560÷8	1600÷8 − 40÷8 = 200−5	195
4) 4824÷24	4800÷24 + 24÷24 = 200+1	201
5) 168÷8	Halve 3 times: 168→84→42→21	21
6) 144÷4	Halve 2 times: 144→72→36	36

Let Us Solve (a-h).

Solution

Problem	Answer
(a) 256÷4	64
(b) 545÷5	109
(c) 147÷7	21
(d) 1212÷6	202
(e) 648÷12	54
(f) 9648÷48	201
(g) 775÷25	31
(h) 796÷4	199

🥥 Susie's Farm & Let Us Learn to Divide

582÷6 coconuts; bags needed; 535÷25 for remaining coconuts.

Solution

582÷6 = 97 coconuts each (worked example — Sunitha's method is more efficient, using bigger chunks like 90 instead of many small steps of 20)

97 coconuts in 25-coconut bags: 3 bags=75, need 1 more bag for remaining 22 → 4 bags(given)

Remaining for drying: 1117−582=535. 535÷25 = 21 bags + 1 more for 10 leftover = 22 bags(given)

726÷4 and 902÷16 — find remainders; is N=D×Q true?

Solution

726÷4: quotient=181, check 4×181=724 (NOT 726) → Answer: No. So 726 = 4×181+2

902÷16: quotient=56, check 16×56=896 (NOT 902) → Answer: No. So 902 = 16×56+6

✏️ Let Us Solve — Word Problems

Q1. Rani: 250 guests, samosas in packs of 6 or 8. Which pack?

Solution

Pack size	Packs needed (rounded up)	Total samosas	Extra (waste)
6 per pack	42 packs	252	2
8 per pack	32 packs	256	6

Packs of 6 give the LEAST waste (only 2 extra samosas), though it needs buying more packs overall (42 vs 32). If minimizing leftover food matters most, choose packs of 6!

Q2. 342 students, buses hold max 41. Buses needed?

Solution

342÷41 = 8 remainder 14 (8 buses hold only 328, not enough)

Need 9 buses (rounding up to fit everyone)

Q3. Sofia pays ₹520 using ₹50 and ₹20 notes — find combinations.

Solution

₹50 notes	₹20 notes	Check
0	26	0+520=520 ✓
2	21	100+420=520 ✓
4	16	200+320=520 ✓
6	11	300+220=520 ✓
8	6	400+120=520 ✓
10	1	500+20=520 ✓

6 possible combinations! Notice: the number of ₹50 notes must always be EVEN.

Q4. 3 friends split ₹157+₹124+₹136 equally.

Solution

Total = 157+124+136 = 417. Each pays 417÷3 = ₹139

Q5. Find remainders; check N=D×Q+R.

Solution

Problem	Q	R	Check
(a) 887÷3	295	2	3×295+2=887 ✓
(b) 283÷8	35	3	8×35+3=283 ✓
(c) 745÷5	149	0	5×149=745 ✓
(d) 767÷26	29	13	26×29+13=767 ✓
(e) 530÷41	12	38	41×12+38=530 ✓
(f) 888÷67	13	17	67×13+17=888 ✓

🥥 Kalpavruksha Coconut Oil

Q1. 4376 coconuts, 8 per litre oil. Earnings at ₹175/L?

Solution

4376÷8 = 547 litres(given/worked example)

Earnings = 547×175 = ₹95,725

Q2. ₹9913 earned selling husk at ₹23/kg. Quantity sold?

Solution

9913÷23 = 431 kg(given/worked example)

Q3. Tender coconuts at ₹35 each, Ibrahim earns ₹8890. How many sold? Extra earned vs ₹20 cost?

Solution

8890÷35 = 254 tender coconuts (exact, no remainder: 35×254=8,890)

Cost at ₹20 each: 254×20 = ₹5,080

Extra earned = 8890 − 5080 = ₹3,810

📐 Division Using Place Value

Worked examples: 62÷5, 75÷8, 324÷3, 136÷6. How to predict quotient digit count?

Solution

Problem	Quotient	Remainder
62÷5	12	2
75÷8	9	3
324÷3	108	0
136÷6	22	4

🌟 Predicting quotient digits: Compare the FIRST digit(s) of the dividend to the divisor. If the leading part of the dividend is bigger than or equal to the divisor, the quotient has (dividend digits − divisor digits + 1) digits. If smaller, it has (dividend digits − divisor digits) digits.

Example: In 324÷3 (3-digit ÷ 1-digit), since "3" (first digit) ≥ divisor 3, quotient has 3−1+1=3 digits (108 ✓). In 75÷8 (2-digit÷1-digit), since "7" < 8, quotient has 2−1=1 digit (9 ✓).

➗ Let Us Divide (a-d)

Complete the four long-division problems.

Solution

Problem	Quotient	Remainder
(a) 7,032÷6	1,172	0 (given)
(b) 3,005÷5	601	0
(c) 2,874÷14	205	4
(d) 9,805÷32	306	13

💡 In (b), we write a 0 in the Tens place of the quotient because 0 Tens (from splitting) ÷ 5 gives 0 — this 0 is a genuine placeholder, not something to skip!

✍️ Let Us Do — Missing Numbers & Riddle

Find missing numbers (no remainder); solve the riddle.

Solution

Problem	Answer
480÷4	120
906÷3	302
400÷20	20
100÷50	2

💡 For the remaining fill-in-the-blank problems on this page, apply the same approach: find a divisor/dividend pair that divides EVENLY (no remainder) — the question itself notes there may be MORE THAN ONE correct answer!

Riddle: "3-digit number, ÷5=42, ×2=420" → If N÷5=42, then N=210. Check: 210×2=420 ✓

The number is 210

✏️ Let Us Solve — Final Word Problems

Q1. Theatre 45 capacity: shows for 475 people; days for 2 shows/day.

Solution

(a) 475÷45 = 10 remainder 25 → need 11 shows

(b) 11 shows ÷ 2 per day = 5.5 → need 6 days

Q2. 5kg ice cream, 23 friends, 400g left. Each friend's share?

Solution

Distributed = 5000−400 = 4,600g. Each friend = 4600÷23 = 200 g

Q3. 15 packets×8 biscuits, 4-day trip, 6 people. Biscuits/person/day?

Solution

Total biscuits = 15×8=120. Person-days = 6×4=24. Each person each day = 120÷24 = 5 biscuits

Q4. Divide and find remainders (a-f).

Solution

Problem	Q	R
(a) 9,045÷5	1,809	0
(b) 1,034÷4	258	2
(c) 2,504÷7	357	5
(d) 8,900÷15	593	5
(e) 9,876÷32	308	20
(f) 7,506÷24	312	18

Q5. Use the pattern from A to solve B and C.

Solution

Part A	Answer	Part B	Answer	Part C	Answer
340÷17	20	192÷8	24	704÷22	32
680÷17	40	384÷8	48	704÷11	64
680÷34	20	384÷4	96	352÷22	16
170÷17	10	384÷8	48	1,408÷44	32
680÷68	10	86÷2	43

🌟 Key pattern: if you DOUBLE both dividend and divisor, the quotient stays the SAME! If you double only the dividend (keep divisor same), the quotient DOUBLES too.

Q6. Cycle rally 576km in 12 days.

Solution

(a) 576÷12 = 48 km/day

(b) This part needs MORE INFORMATION — specifically, how much distance was already covered (or how many days already used) before reaching Ratnagiri. Without that, we can't calculate the daily distance for the remaining 4 days to Goa.

Q7. Identify missing information in each problem.

Solution

Part	Missing Info
(a) Mango vendor	Price per mango (or per basket) — can't find total earnings without it
(b) School desks	Total number of desks in the school — can't find per-classroom count without it
(c) Cricket bats	No info missing! ₹3,500÷5 = ₹700 per bat — directly answerable
(d) Idli plates	Price of a SINGLE idli (only total earnings and plate count are given, not idlis-per-plate directly)

Q8. Carpenter's bookshelf materials — max shelves possible?

Solution

Material	Stock	Needed/shelf	Max shelves from this
Long panels	264	4	66
Short panels	306	8	38 (rounded down)
Small clips	2,400	16	150
Large clips	120	4	30 ← LIMITING
Screws	2,800	32	87 (rounded down)

Maximum shelves = 30 — limited by LARGE CLIPS (the scarcest resource)! Even though other materials could make many more shelves, you can't exceed what the smallest-supply item allows.

🥕 Vegetable Market & Final Divisions

Complete Munshi Lal's vegetable record table.

Solution

Vegetable	Cost/kg	Quantity	Total
Radish	₹26	78 kg	₹2,028
Potato	₹20	112 kg	₹2,240
Cabbage	₹32	56 kg	₹1,792
Green peas	₹25	125 kg	₹3,125
Total earned			₹9,185

Divide 1-12, identify remainders, check N=D×Q+R.

Solution

#	Problem	Q	R
1	506÷5	101	1
2	918÷8	114	6
3	8,126÷7	1,160	6
4	9,324÷4	2,331	0
5	876÷6	146	0
6	7,008÷3	2,336	0
7	934÷12	77	10
8	829÷23	36	1
9	705÷18	39	3
10	8,704÷32	272	0
11	6,790÷45	150	40
12	5,074÷21	241	13

✅❌ Mathematical Statements

Q1. True or False?

Solution

Statement	Check	T/F
(a) 8×9=70+2	72 vs 72	True
(b) 20−6=7×3	14 vs 21	False
(c) 48÷3=4×4	16 vs 16	True
(d) 89−9=90+0	80 vs 90	False
(e) 25+10=45−10	35 vs 35	True

Q2. Complete to make true statements.

Solution

Statement	Answer
(a) 7×6 = ___+17	42=___+17 → 25
(b) 87+6 = ___×31	93=___×31 → 3
(c) 63+___ = 74−4	63+___=70 → 7
(d) ___÷9 = 16÷2	___÷9=8 → 72

Q3. Explore always/never/sometimes true statements.

Solution

(a) "Odd+Odd=Even" — ALWAYS TRUE. Examples: 1+3=4, 5+7=12, 9+11=20, 13+15=28, 17+19=36. No exception possible — this is mathematically guaranteed!

(b) "Multiplying by 2 can give odd" — NEVER TRUE. Any number×2 is always even by definition. No example exists.

(c) "Halving always gives even" — SOMETIMES TRUE. True: half of 8=4, half of 12=6, half of 20=10. False: half of 6=3, half of 10=5, half of 14=7.

Q4. Tick Always/Sometimes/Never for each statement.

Solution

Statement	Answer
Adding 10 gives a multiple of ten	Sometimes True (only if original number already ended in 0)
Changing order in subtraction makes no difference	Never True (5−3 ≠ 3−5)
Doubling one number, halving the other keeps product same	Always True
Multiplication by an odd number gives even	Sometimes True (odd×even=even, but odd×odd=odd)
Multiplying by 5 gives Ones digit 0	Sometimes True (only when multiplying an EVEN number; 5×odd ends in 5, not 0)