Two wires of same length and same area of cross-section but made of...

Question

Two wires of same length and same area of cross-section but made of different material of resistivities 1 and 2 are connected in series. The equivalent resistivity of the combination is :

Accepted Answer

Same length $L$, same area $A$, resistivities $\rho_1$, $\rho_2$, in series:

$R_1=\rho_1L/A$, $R_2=\rho_2L/A$, total $R=R_1+R_2=(\rho_1+\rho_2)L/A$

Since the combination has total length $2L$ and area $A$, define equivalent resistivity via $R=\rho_{eq}(2L)/A$:

$$\rho_{eq}=\frac{\rho_1+\rho_2}{2}$$

💬 Doubts & Comments

Abhi tak koi comment nahi

Apna comment likhein

💬 Doubts & Comments

Abhi tak koi comment nahi

Apna comment likhein

🔔 Email Updates Lein