📌 Standard Network (C₁ = C₃ = C₄ = 100 pF, C₂ = 200 pF):

Step 1 — Identify Series/Parallel Groups:

• C₂ and C₃ are in <b>series</b>:
  1/C₂₃ = 1/200 + 1/100 = 3/200 → C₂₃ = 200/3 pF
  • C₂₃ and C₄ are in <b>parallel</b>:
    C₂₃₄ = 200/3 + 100 = 500/3 pF
  • C₁ and C₂₃₄ are in <b>series</b>:
    1/C_eq = 1/100 + 3/500 = 5/500 + 3/500 = 8/500
    C_eq = <b>500/8 = 62.5 pF</b>

Step 2 — Total Charge:

Q_total = C_eq × V = 62.5 × 10⁻¹² × 300 = <b>18750 pC ≈ 1.875 × 10⁻⁸ C</b>

Step 3 — Charge Distribution:

• Q on C₁ = Q_total (series) = <b>1.875 × 10⁻⁸ C</b>
  • Voltage across C₂₃₄ = V − V_C₁ = 300 − (Q/C₁) = 300 − 187.5 = <b>112.5 V</b>
  • Q on C₄ = C₄ × 112.5 = 100×10⁻¹² × 112.5 = <b>1.125 × 10⁻⁸ C</b>
  • Q on C₂ = Q on C₃ = Q_total − Q_C₄ = <b>0.75 × 10⁻⁸ C</b>