[Case Study, Q29 contd.] (ii) Two cells of emfs 2.0 V and 6.0 V, wi...

Question

[Case Study, Q29 contd.] (ii) Two cells of emfs 2.0 V and 6.0 V, with internal resistances $0.1\Omega$ and $0.4\Omega$ respectively, are connected in parallel. Find the equivalent emf of the combination.

Accepted Answer

Step 1: For cells in parallel, equivalent emf (Millman's theorem): $\varepsilon_{eq} = \dfrac{\varepsilon_1/r_1+\varepsilon_2/r_2}{1/r_1+1/r_2}$.

Step 2: $= \dfrac{2/0.1+6/0.4}{1/0.1+1/0.4} = \dfrac{20+15}{10+2.5} = \dfrac{35}{12.5} = 2.8$ V.

Step 3: Answer: (B) 2.8 V.

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