A parallel plate air capacitor is charged to a potential difference...

Question

A parallel plate air capacitor is charged to a potential difference of V. If distance between the plates is increased (battery disconnected), then potential difference between the plates

Accepted Answer

✅ Correct Answer: (B) Increases

📌 Condition: Capacitor is disconnected from battery → Charge Q = constant

Step 1 — Effect on Capacitance:

C = ε₀A / d

As d ↑, C ↓

Step 2 — Effect on Potential:

V = Q / C

As C ↓ and Q is constant → V increases

∴ Potential difference increases when plate separation is increased.

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