A current of 10 A is maintained in a conductor of cross-section $10...

Question

A current of 10 A is maintained in a conductor of cross-section $10^{-4}$ m$^2$. If number density of free electrons is $9 	imes 10^{28}$ m$^{-3}$, calculate the drift velocity. ($e = 1.6 	imes 10^{-19}$ C)

Accepted Answer

Using $I = nAev_d$: $$v_d = \frac{I}{nAe} = \frac{10}{9 	imes 10^{28} 	imes 10^{-4} 	imes 1.6 	imes 10^{-19}} = \frac{10}{14.4 	imes 10^{5}} \approx 6.94 	imes 10^{-6} 	ext{ m/s}$$

💬 Doubts & Comments

Abhi tak koi comment nahi

Apna comment likhein

💬 Doubts & Comments

Abhi tak koi comment nahi

Apna comment likhein

🔔 Email Updates Lein