CBSE
2026
Class Class 10 · Mathematics
1 Marks · Mcq
✅ Verified
The roots of the quadratic equation $4x^2 - (a-1)^2 = 0$ are :
A. $a - 1,\ a + 1$
B. $\dfrac{a-1}{2},\ \dfrac{-a+1}{2}$
C. $\dfrac{a-1}{2},\ \dfrac{-a-1}{2}$
D. $\pm(a-1)$
✅ Answer & Solution
✅ Correct Answer: B
Step 1: $$4x^2 - (a-1)^2 = 0 \Rightarrow 4x^2 = (a-1)^2$$
Step 2: $$x^2 = \frac{(a-1)^2}{4}$$
Step 3: $$x = \pm\frac{a-1}{2}$$
Step 4: Hence the roots are $\dfrac{a-1}{2}$ and $\dfrac{-(a-1)}{2} = \dfrac{-a+1}{2}$.
Correct option : (B)
✅ Verified by Super Admin