The number of multiples of $4$ lying between $12$ and $250$ is :

Question

Accepted Answer

Step 1: The multiples of $4$ strictly between $12$ and $250$ form an A.P. :
$$16,\ 20,\ 24,\ \ldots,\ 248$$
Step 2: Here $a = 16$, $d = 4$, $a_n = 248$.
Step 3: $$a_n = a + (n-1)d \Rightarrow 248 = 16 + (n-1)4$$
$$232 = 4(n-1) \Rightarrow n - 1 = 58 \Rightarrow n = 59$$

Correct option : (A)

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