From a point on the ground, which is 60 m away from the foot of a v...

Question

From a point on the ground, which is 60 m away from the foot of a vertical tower, the angle of elevation of the top of the tower is found to be $45^\circ$. The height (in metres) of the tower is :

Accepted Answer

**Step 1 — Draw and label.**
Let $AB$ = tower of height $h$, $B$ = foot, $C$ = point on the ground with $BC = 60$ m and $\angle ACB = 45^\circ$.

**Step 2 — Use the tangent ratio in right $	riangle ABC$.**
$$	an 45^\circ = \frac{AB}{BC} = \frac{h}{60}$$

**Step 3 — Substitute $	an 45^\circ = 1$.**
$$1 = \frac{h}{60} \ \Rightarrow\ h = 60 	ext{ m}$$

**Answer : (C) 60**

🔔 Email Updates Lein