**Step 1 — Set $p(x) = 0$.**
$$(x-2)(x+3) = 0$$

**Step 2 — Use the zero-product rule.**
$$x - 2 = 0 \ \Rightarrow\ x = 2 \qquad \text{or} \qquad x + 3 = 0 \ \Rightarrow\ x = -3$$

**Step 3 — Count the zeroes.**
The zeroes are $2$ and $-3$, i.e. **two** zeroes.

(Consistent with the rule: a quadratic polynomial has at most 2 zeroes.)

**Answer : (C) Two**