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Class 12 › Physics › Electric Charge and Field
CBSE2024Class Class 12 · Physics2 Marks · Short✅ Verified
A charge "Q" is divided into two parts such that the electrostatic force between two parts is maximum. Find the charge on each part.
✅ Answer & Solution
<b>Setup:</b><br>Let one part be q and the other part be (Q - q).<br><br><b>Step 1: Express the force</b><br>Using Coulomb's law (with fixed distance r):<br>F = k · q · (Q - q)/r²<br>F = (k/r²) · (qQ - q²)<br><br><b>Step 2: For maximum force, differentiate F w.r.t. q</b><br>dF/dq = (k/r²) · (Q - 2q)<br><br><b>Step 3: Set derivative = 0</b><br>Q - 2q = 0<br><b>q = Q/2</b><br><br><b>Step 4: Verify it's a maximum</b><br>d²F/dq² = -2k/r² < 0 ✓ (Maximum confirmed)<br><br><b>Step 5: Charges on each part</b><br>First part = q = <b>Q/2</b><br>Second part = Q - q = Q - Q/2 = <b>Q/2</b><br><br><b>Conclusion:</b><br>The charge must be <b>divided into two equal halves (Q/2 and Q/2)</b> for maximum force.<br><br><b>Maximum force:</b><br>F<sub>max</sub> = k · (Q/2) · (Q/2)/r² = kQ²/(4r²)