CBSE
2024
Class Class 12 · Physics
1 Marks · Mcq
✅ Verified
Two point charges each equal to 2 mC are 0.5 m apart. If both of them exist inside vacuum, then electrostatic force between them is:
A. 1.44 × 10⁵ N
B. 1.44 × 10⁴ N
C. 1.44 × 10³ N
D. 1.44 × 10² N
✅ Answer & Solution
✅ Correct Answer: A
<b>Given:</b><br>q<sub>1</sub> = q<sub>2</sub> = 2 mC = 2 × 10⁻³ C<br>r = 0.5 m<br>k = 9 × 10⁹ N·m²/C²<br><br><b>Formula (Coulomb's Law):</b><br>F = kq<sub>1</sub>q<sub>2</sub>/r²<br><br><b>Calculation:</b><br>F = (9 × 10⁹) × (2 × 10⁻³) × (2 × 10⁻³) / (0.5)²<br><br>F = (9 × 10⁹ × 4 × 10⁻⁶) / 0.25<br><br>F = (36 × 10³) / 0.25<br><br>F = <b>1.44 × 10⁵ N</b><br><br><b>Answer:</b> Option (A) 1.44 × 10⁵ N
✅ Verified by Super Admin