If value of $\cot heta$ is $\sqrt5$, then $\sin heta$ equals:

Question

If value of $\cot	heta$ is $\sqrt5$, then $\sin	heta$ equals:

Accepted Answer

Using right triangle: base $=\sqrt5$, perpendicular$=1$, hypotenuse$=\sqrt{5+1}=\sqrt6$. $$\sin	heta=\frac{1}{\sqrt6}$$