CBSE
2026
Class Class 10 · Mathematics
1 Marks · Mcq
✅ Verified
PT is tangent to the circle with centre O and radius 5 cm. OP intersects the circle at Q. If PQ = x, then PT² equals:
A. x² + 5x
B. x² + 10x + 50
C. x² + 10x
D. x² - 25
✅ Answer & Solution
✅ Correct Answer: C
$OP = OQ+QP = 5+x$. Since $PT \perp OT$ (radius), by Pythagoras: $$PT^2=OP^2-OT^2=(x+5)^2-5^2=x^2+10x+25-25=x^2+10x$$
✅ Verified by Super Admin
