CBSE
2026
Class Class 10 · Mathematics
1 Marks · Mcq
✅ Verified
In the given figure, PA is a tangent from an external point P to a circle with centre O. If $\angle POB = 125°$, then $\angle APO$ is equal to:
A. 25°
B. 65°
C. 90°
D. 35°
✅ Answer & Solution
✅ Correct Answer: D
Since $OA \perp PA$ (tangent $\perp$ radius), $\angle OAP = 90°$. From the figure, $\angle AOP = 180° - 125° = 55°$. In right triangle OAP: $\angle APO = 180° - 90° - 55° = 35°$.
✅ Verified by Super Admin
